
Dry Bulbs, Wet Bulbs,
and My Will to Live:
Mastering the Psych Chart
DOFPro Team










You set out a cold root brew on a day when the temperature is 86 degrees Fahrenheit, which you may recall was \(30\ ^\circ\mathrm{C}\), and the relative humidity is \(30\%\).

\[\colorbox{white}{$\displaystyle T_\mathrm{dp} = 10.55\ ^\circ\mathrm{C}$}\]
\[\colorbox{white}{$\displaystyle T_\mathrm{wb} = 17.95\ ^\circ\mathrm{C}$}\]
\[\colorbox{white}{$\displaystyle h_a = 0.00795\ \mathrm{kg\ H_2O/kg\ DA}$}\]
\[\colorbox{white}{$\displaystyle \hat{V} = 0.870\ \mathrm{m^3/kg\ DA}$}\]
\[\colorbox{white}{$\displaystyle \hat{H}_\mathrm{sat} = 50.86\ \mathrm{kJ/kg\ DA}$}\]
\[\colorbox{white}{$\displaystyle \hat{H}_\mathrm{dev} = -0.37\ \mathrm{kJ/kg\ DA}$}\]
\[\colorbox{white}{$\displaystyle \hat{H} = \hat{H}_\mathrm{sat} + \hat{H}_\mathrm{dev} = 50.86 - 0.37 = 50.49\ \mathrm{kJ/kg\ DA}$}\]
We have hot air at \(43\ ^\circ\mathrm{C}\) and \(10\%\ h_r\) entering an adiabatic clothes dryer containing 5 kg of water and assorted clothes and exiting at \(90\%\ h_r\).

\[\colorbox{white}{$\displaystyle h_a = 0.0054\ \mathrm{kg\ H_2O/kg\ DA}$}\]
\[\colorbox{white}{$\displaystyle h_a = 0.0144\ \mathrm{kg\ H_2O/kg\ DA}$}\]
\(m_\mathrm{DA} = \dfrac{5}{0.0144 - 0.0054} = 556\ \mathrm{kg\ DA}\)
\[\colorbox{white}{$\displaystyle \color{purple}\hat{V} = 0.903\ \mathrm{m^3/kg\ DA}$}\]
\(V = m_\mathrm{DA} \hat{V} = 556 \cdot 0.903 = \boxed{502\ \mathrm{m^3\ DA}}\)
\[\colorbox{white}{$\displaystyle \boxed{\color{blue}T_\mathrm{db} = 21.27\ ^\circ\mathrm{C}}$}\]
\[\colorbox{white}{$\displaystyle \boxed{\color{green}T_\mathrm{wb} = 20.1\ ^\circ\mathrm{C}}$}\]
Thanks for watching!
The previous video in the series is in the link in the upper left. The next video in the series is in the upper right. To learn more about Chemical and Thermal Processes, visit the website linked in the description.
The DOFPro Team
