DOFPro Team

Most commercial reactors are heterogeneous reactors.
We will focus first on the ideal homogeneous reactors.
Note
We will not derive the transient cases for CSTRs or PFRs, but they are critically important during
plant start-up and shut-down.
We will rewrite our chemical reactions by dividing through by the absolute value of the stoichiometric coefficient for species \(\mathrm{A}\), giving a result of the form,
\[ \mathrm{A} + \frac{\nu_\mathrm{B}}{|\nu_\mathrm{A}|} \mathrm{B} + \cdots \rightarrow \frac{\nu_\mathrm{P}}{|\nu_\mathrm{A}|} \mathrm{P} + \frac{\nu_\mathrm{S}}{|\nu_\mathrm{A}|} \mathrm{S} + \cdots \]
Essentially every chemical reactor class ever follows this practice.
With \(r_\mathrm{A}\) equal to \(\nu_\mathrm{A} r = - r\), we will limit ourselves at the present time to irreversible reactions with kinetics of the form
\[ -r_\mathrm{A} = k C_\mathrm{A}^n C_\mathrm{B}^m \]
For our transient, spatially uniform, constant-volume batch reactor

\[ \dot{n}_{j_0} - \dot{n}_j + \int_{V_R} r_j dV = \frac{dn_j}{dt} \]
\[ r_j \ne r_j(\mathrm{position)}) \implies \int_{V_R} r_j dV = r_j \int_{V_R} dV = r_j V_R \]
or
\[ \frac{1}{V_R} \frac{dn_j}{dt} = r_j\ \ \text{ or }\ \ \frac{dC_j}{dt} = r_j \]
For Species A (constant \(V_R\))
\[ n_\mathrm{A} = n_\mathrm{A_0} (1- f_\mathrm{A}) \]
and
\[ \frac{1}{V_R}\frac{dn_\mathrm{A}}{dt} = \frac{n_\mathrm{A_0}}{V_R}\frac{d(1- f_\mathrm{A})}{dt} = -C_\mathrm{A_0} \frac{df_\mathrm{A}}{dt} \]
or \[ \frac{1}{V_R}\frac{dn_\mathrm{A}}{dt} = \frac{dC_\mathrm{A}}{dt} \]
In terms of \(f_\mathrm{A}\)
\[ -C_\mathrm{A_0} \frac{df_\mathrm{A}}{dt} = r_\mathrm{A} \]
\[ \int_0^t dt = C_\mathrm{A_0} \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{(-r_\mathrm{A})} \]
\[ t = C_\mathrm{A_0} \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{(-r_\mathrm{A})} \]
In terms of \(C_\mathrm{A}\)
\[ \frac{dC_\mathrm{A}}{dt} = r_\mathrm{A} \]
\[ \int_0^t dt = \int_{C_\mathrm{A_0}}^{C_\mathrm{A}} \frac{dC_\mathrm{A}}{r_\mathrm{A}} \]
\[ t = \int_{C_\mathrm{A_0}}^{C_\mathrm{A}} \frac{dC_\mathrm{A}}{r_\mathrm{A}} \]
In terms of \(f_\mathrm{A}\)
\[ t = C_\mathrm{A_0} \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{(-r_\mathrm{A})} \]

In terms of \(C_\mathrm{A}\)
\[ t = \int_{C_\mathrm{A_0}}^{C_\mathrm{A}} \frac{dC_\mathrm{A}}{r_\mathrm{A}} \]

\(0\)
\(f_\mathrm{A}\)
\(\frac{C_\mathrm{A_0}}{(-r_\mathrm{A})}\)
\(\mathrm{Area} = t\)
\(0\)
\(C_\mathrm{A_0}\)
\(C_\mathrm{A}\)
\(\frac{1}{(-r_\mathrm{A})}\)
\(\mathrm{Area} = t\)

Steady state, spatially uniform
\[ \dot{n}_{j_0} - \dot{n}_j + \int_{V_R} r_j dV = \frac{dn_j}{dt} \]
\[ r_j \ne r_j(\mathrm{position)} \implies \dot{n}_{j_0} - \dot{n}_j + r_j V_R = 0 \]
\[ \dot{n}_{j_0} = \dot{n}_j + (-r_j) V_R \]
For species \(\mathrm{A}\),
\[ V_R = \frac{\dot{n}_\mathrm{A_0}-\dot{n}_\mathrm{A}}{-r_\mathrm{A}} \]
Define the space time, \(\tau \equiv \frac{V_R}{\dot{V}_0}\)
In terms of \(f_\mathrm{A}\)
\(\ \ \ \ \dot{n}_\mathrm{A} = \dot{n}_\mathrm{A_0}(1 - f_\mathrm{A})\)
\(\ \ \ \ (-r_\mathrm{A}) V_R = \dot{n}_\mathrm{A_0}(f_\mathrm{A})\)
and
\(\ \ \ \ \dot{n}_\mathrm{A_0}=\dot{V}_0 C_\mathrm{A_0}\)
then
\(\ \ \ \ \tau = \frac{V_R}{\dot{V}_0} = \frac{C_\mathrm{A_0}f_\mathrm{A}}{{-r_\mathrm{A}}}\)
In terms of \(C_\mathrm{A}\)
\(\ \ \ \ \dot{V}_0 = \dot{V}\)
\(\ \ \ \ \dot{n}_\mathrm{A_0} = \dot{V}_0C_\mathrm{A_0}\)
\(\ \ \ \ \dot{n}_\mathrm{A} = \dot{V}_0C_\mathrm{A}\)
then
\(\ \ \ \ \tau = \frac{V_R}{\dot{V}_0} = \frac{C_\mathrm{A_0}- C_\mathrm{A}}{{-r_\mathrm{A}}}\)
In terms of \(f_\mathrm{A}\)
\(\ \ \ \ \tau = \frac{V_R}{\dot{V}_0} = \frac{C_\mathrm{A_0}f_\mathrm{A}}{{-r_\mathrm{A}}}\)

In terms of \(C_\mathrm{A}\)
\(\ \ \ \ \tau = \frac{V_R}{\dot{V}_0} = \frac{C_\mathrm{A_0}- C_\mathrm{A}}{{-r_\mathrm{A}}}\)

\(0\)
\(f_\mathrm{A}\)
\(\frac{C_\mathrm{A_0}}{(-r_\mathrm{A})}\)
\(\mathrm{Area} = \tau\)
\(0\)
\(C_\mathrm{A_0}\)
\(C_\mathrm{A}\)
\(\frac{1}{(-r_\mathrm{A})}\)
\(\mathrm{Area} = \tau\)

Steady state, radially uniform, axially varies
Differential Element

\(\dot{n}_j\)
\(\dot{n}_j+d\dot{n}_j\)
\(dV\)
\[ \dot{n}_j - (\dot{n}_j + d\dot{n}_j) + r_j dV = \frac{dn_j}{dt} \]
\[ \frac{d\dot{n}_j}{dV} = r_j \]
For reactant \(\mathrm{A}\)
\[ \int_0^{V_R} dV = \int_{\dot{n}_\mathrm{A0}}^{\dot{n}_\mathrm{A}} \frac{d\dot{n}_\mathrm{A}}{r_\mathrm{A}}, \]
\[ V_R = \int_{\dot{n}_\mathrm{A0}}^{\dot{n}_\mathrm{A}} \frac{d\dot{n}_\mathrm{A}}{r_\mathrm{A}} \]
To get the expression in terms of \(f_\mathrm{A}\), as before
\(\ \ \ \ \ \ \ \dot{n}{_\mathrm{A}} = \dot{n}{_\mathrm{A0}} ( 1 - f_\mathrm{A})\)
and
\(\ \ \ \ \ \ \ d\dot{n}{_\mathrm{A}} = -\dot{n}{_\mathrm{A0}} df_\mathrm{A}\)
Making the substitutions and dividing by \(\dot{n}_\mathrm{A0}\)
\[ \frac{V_R}{\dot{n}_\mathrm{A0}} = \frac{\tau}{C_\mathrm{A0}} = \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{(-r_\mathrm{A})} \]
or
\[ \tau = C_\mathrm{A0} \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{(-r_\mathrm{A})} \]
In terms of \(C_\mathrm{A}\)
\[ \tau = \int_{C_\mathrm{A0}}^{C_\mathrm{A}} \frac{dC_\mathrm{A}}{r_\mathrm{A}} \]
In terms of \(f_\mathrm{A}\) \[
\tau = C_\mathrm{A_0} \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{(-r_\mathrm{A})}
\] 
In terms of \(C_\mathrm{A}\) \[
\tau = \int_{C_\mathrm{A_0}}^{C_\mathrm{A}} \frac{dC_\mathrm{A}}{r_\mathrm{A}}
\] 
\(0\)
\(f_\mathrm{A}\)
\(\frac{C_\mathrm{A_0}}{(-r_\mathrm{A})}\)
\(\mathrm{Area} = \tau\)
\(0\)
\(C_\mathrm{A_0}\)
\(C_\mathrm{A}\)
\(\frac{1}{(-r_\mathrm{A})}\)
\(\mathrm{Area} = \tau\)
Batch
\[ t = - \int_{C_\mathrm{A0}}^{C_\mathrm{A}} \frac{dC_\mathrm{A}}{k C_\mathrm{A}} \]
\[ t=\frac{1}{k}\ln \frac{C_\mathrm{A0}}{C_\mathrm{A}} \]
PFR
\[ \tau = - \int_{C_\mathrm{A0}}^{C_\mathrm{A}} \frac{dC_\mathrm{A}}{k C_\mathrm{A}} \]
\[ \tau=\frac{1}{k}\ln \frac{C_\mathrm{A0}}{C_\mathrm{A}} \]
CSTR
\[ \tau = - \frac{C_\mathrm{A0} - C_\mathrm{A}} {k C_\mathrm{A}} \]
\[ \tau=\frac{1}{k} \left( \frac{C_\mathrm{A0}}{C_\mathrm{A}} - 1 \right) \]
or
\[ t = {C_\mathrm{A0}} \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{k C_\mathrm{A0}(1-f_\mathrm{A})} \]
\[ t = - \frac{1}{k}\ln (1-f_\mathrm{A}) \]
\[ \tau = {C_\mathrm{A0}} \int_0^{f_\mathrm{A}} \frac{df_\mathrm{A}}{k C_\mathrm{A0}(1-f_\mathrm{A})} \]
\[ \tau = - \frac{1}{k}\ln (1-f_\mathrm{A}) \]
\[ \tau = \frac{{C_\mathrm{A0}f_\mathrm{A}} } {k C_\mathrm{A0}(1-f_\mathrm{A})} \]
\[ \tau = \frac{{f_\mathrm{A}} } {k (1-f_\mathrm{A})} \]
Thanks for watching!
The previous video in the series is in the link in the upper left. The next video in the series, is in the upper right. To learn more about Chemical and Thermal Processes, visit the website linked in the description.

