DOFPro Team

Oh, Henry! is an introduction to the relationship between vapor pressure and temperature for a pure component, and for how to treat phase equilibrium for a two-phase vapor-liquid system when only one of the two components is below its critical point and can condense.
For one component, how do you calculate phase equilibria?
https://commons.wikimedia.org/wiki/File:Phase-diag2.svg
1-Component Vapor-Liquid Equilibrium (VLE)
From Wikipedia comes the Clapeyron equation:
\[ \frac{dp^*}{dT} = \frac{\Delta \hat{H}_{v}}{T(\hat{V}_{g} - \hat{V}_l)} \]
Where \(p^*\) is the vapor pressure.
If \(\hat{V}_g \gg \hat{V}_l\), and the vapor is ideal, then:
\[ \frac{d(\ln p^{*})}{d(1/T)} = - \frac{\Delta \hat{H}_{v}}{R} \]
If in addition, \(\Delta \hat{H}_v\) is constant, we can integrate to
\[ \ln p^{*} = -\frac{\Delta \hat{H}_v}{RT} + B \]
which is the Clausius-Clapeyron equation.
Empirical equations are also used. The simplest with reasonable accuracy is the Antoine equation:
\[ \log_{10} p^{*} = A - \frac{B}{T + C} \]
where \(A\), \(B\), and \(C\) are constants from a reference source such as the NIST Chemistry WebBook. What are \(A\), \(B\), and \(C\) if the substance obeys the Clausius-Clapeyron equation and \(T\) is in \(^\circ\mathrm{C}\)?
1-Condensable component, e.g., ethanol-argon. Assume ideal gas behavior and that species \(i\) is the condensable one, then at saturation (e.g., two-phases present):
\[ p_i = y_{i}P = p^{*}_{i}(T) \]
If the temperature is high enough (or pressure low enough) that only one phase is present then:
\[ p_i = y_{i}P < p^{*}_{i}(T) \]
At what temperature will condensation begin?
\[ p_i = y_{i}P = p^{*}_{i}(T_{dp}) \]
\(T_{dp}\) is the dew-point temperature. The difference between
\(T\) and \(T_{dp}\) is the degree(s) of superheat.
You are standing in the shower with the air and water temperature at 35 °C. What mole-fraction of the air that you are breathing is water?
\[ p_{i} = y_{i}P = p^{*}_{i}(T) \]
\[ y_{i} = \frac{p_{i}^{*}(T)}{P} \]
Get \(p_{i}^{*}\) from the Antoine equation, from the Steam Table, or from DWSIM.

Most people don’t understand mole fractions, and we don’t have enough parameter names yet, so we have the following definitions (saturation is any gas-vapor system, humidity is specifically air-water):
Relative Saturation or Relative Humidity
\[s_r \text{ or }h_r = \frac{p_i}{p_i^*(T)}*100%\]
Molal Saturation or Molal Humidity
\[s_m\text{ or }h_m = \frac{p_i} {P-p_i} = \frac{\text{moles of vapor}}{\text{moles of vapor-free (dry)gas}}\]
Absolute Saturation or Absolute Humidity
\[s_a\text{ or }h_a = \frac{p_{i} M_{i}} {(P-p_i)M_{dry}} = \frac{\text{moles of vapor}}{\text{moles of vapor-free (dry)gas}}\]
Percentage Saturation or Percentage Humidity
\[s_p\text{ or }h_p = 100\% \times \frac{s_m} {s_m^*} = 100\% \times \frac{\frac{p_i}{P-p_i}}{\frac{p_i^*}{P-p_i^*}}\]
You set out a cold (root)brew on a day when the temperature is \(86\ ^\circ\mathrm{F}\) and the relative humidity is \(30\%\).
Solution:
Need \(p^*\) at \(86\ ^\circ\mathrm{F}\) (\(30\ ^\circ\mathrm{C}\))
From Antoine Equation or Steam Table or DWSIM.
Antoine Equation
\[\log_{10}p^* = 4.6543 - \frac{1435.264}{T - 64.848}\]
\[= 4.6543 - \frac{1435.264}{30 - 64.848} = -1.3686\]
\[p^* = 10^{-1.3686} = 0.04280\ \mathrm{bar}\]
\[p = h_rp^* = 0.30 \times 0.04280\ \mathrm{bar} = 0.01284\ \mathrm{bar}\]
\[T_{dp} = \frac{B}{A-\log_{10}p^*} - C\]
\[= \frac{1435.264}{4.6543 − \log_{10} 0.01284} + 64.848 = 10.96\ ^\circ\mathrm{C}\text{ or }51.74\ ^\circ\mathrm{F}\]
\[T-T_{dp} = 30-10.96 = 19.04\ ^\circ\mathrm{C}\text{ or }34.26\ ^\circ\mathrm{F}\text{ of Superheat}\]
Steam Table or DWSIM
\[p^* = 0.04247\ \mathrm{bar}\]
\[p = h_{r}p^{*} = 0.30 \times 0.04247\ \mathrm{bar} = 0.01274\ \mathrm{bar}\]

\[T_{dp} = 10.55\ ^\circ\mathrm{C}\text{ or }50.99\ ^\circ\mathrm{F}\]
\[T - T_{dp} = 30-10.55 = 19.45\ ^\circ\mathrm{C}\text{ or }35.01\ ^\circ\mathrm{F}\text{ of Superheat}\]
What about a gas dissolved in a liquid? For dilute solutions, Henry’s Law holds (A dilute solution is one for which Henry’s law holds).
\[p_\mathrm{A} \equiv y_\mathrm{A}P = x_\mathrm{A}H_\mathrm{A}(T)\]
In words, the fraction of A dissolved in the liquid phase is directly proportional to the partial pressure of A in the vapor phase. The proportionality constant (which can change with temperature) is the Henry’s Law Constant. (See Wikipedia)
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