DOFPro Team
Mass is both a property of a physical body and a measure of its resistance to acceleration (a change in its state of motion) when a net force is applied. An object’s mass also determines the strength of its gravitational attraction to other bodies. (https://en.wikipedia.org/wiki/Mass)
The SI unit of mass, the kilogram, is defined from Planck’s constant
\[h=6.626070150 \times 10^{-34}\ \mathrm{kg \cdot m^2/s}\]
or
\[ 1\ \mathrm{kg}=\frac{h}{6.626070150 \times 10^{-34}\ \mathrm{m^2/s}} \]
For the curious, the second is defined as 9 192 631 770 times the period of the unperturbed ground-state hyperfine transition of the cesium 133 atom, \(\Delta \nu_\mathrm{Cs}\). And the meter is defined as 1/299 792 458th of the distance light travels in a vacuum in one second, \(c\), or
\[1\ \mathrm{kg} = \frac{(299\ 792\ 458)^2}{(6.626\ 070\ 150 \times 10^{-34})(9\ 192\ 631\ 770)} \frac{h\ \Delta \nu_\mathrm{Cs}}{c^2}\]
The American engineering unit of mass, the pound mass, or \(\mathrm{lb_m}\) is defined as
\[1\ \mathrm{lb_m} \equiv 0.453\ 592\ 37\ \mathrm{kg}\]
See What Ia A Mole? for a more thorough explanation
The most common moles are
You should NEVER convert your mass in \(\text{kg}\) or \(\mathrm{lb_m}\) to \(\mathrm{g}\), and then to \(\text{g-mol}\). You should ALWAYS use the kind of mole your mass is in. The conversion factor is simply the molecular weight.
The molecular weight of methane is:
\[M_\mathrm{CH_4} = 16.0425\ \frac{\text{g}}{\text{g-mol}} = 16.0425\ \frac{\text{kg}}{\text{kg-mol}} = 16.0425\ \frac{\mathrm{lb_m}}{\text{lb-mol}}\]
To calculate the pounds of oxygen (\(M = 31.9988\)) required to completely burn three pounds of methane:
\[\mathrm{CH_4} + 2 \mathrm{O_2} \rightarrow \mathrm{CO_2} + 2 \mathrm{H_2O} \implies \frac{2\ \text{lb-mol }\mathrm{O_2}}{1\ \text{lb-mol }\mathrm{CH_4}}\]
\[\frac{3\ \mathrm{lb_m\ CH_4}}{16.0425\ \frac{\mathrm{lb_m\ CH_4}}{\text{lb-mol CH}_4}} \frac{2\ \text{lb-mol }\mathrm{O_2}}{1\ \text{lb-mol }\mathrm{CH_4}} \frac{31.9988\ \mathrm{lb_m\ O_2}}{1\ \text{lb-mol O}_2} = 11.9678\ \mathrm{lb_m\ O_2}\]
Calculating it any other way is just a waste of time and brain effort.
\(x\), \(y\), and \(z\) are all used for both mass fractions and mole fractions.
\(x_\mathrm{A}\) can be the mass fraction of species \(\mathrm{A}\) or the mole fraction of species \(\mathrm{A}\).
Likewise for \(y_\mathrm{A}\) and \(z_\mathrm{A}\).
Convention usually uses:
To convert from mass fraction, \(x\), to mole fraction, \(y\):
\[y_\mathrm{A} = \frac{\frac{x_\mathrm{A}}{M_\mathrm{A}}}{\sum \frac{x_i}{M_i}}\]
To convert from mole fraction, \(y\), to mass fraction, \(x\):
\[x_\mathrm{A} = \frac{y_\mathrm{A} M_\mathrm{A}}{\sum y_i M_i}\]
The mole-averaged (or number-averaged) molecular weight is
\[\bar{M} = \sum y_i M_i = \left(\sum \frac{x_i}{M_i}\right)^{-1}\]
The mass-averaged molecular weight is
\[\bar{M}_m = \sum x_i M_i = \frac{\sum y_i M_i^2}{\sum y_i M_i}\]
The mole-averaged molecular weight is most often used for mixtures of gases.
The mass-averaged molecular weight is most often used for polymers.
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